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x^2+48x-208=0
a = 1; b = 48; c = -208;
Δ = b2-4ac
Δ = 482-4·1·(-208)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-56}{2*1}=\frac{-104}{2} =-52 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+56}{2*1}=\frac{8}{2} =4 $
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